How much grams of solute in 168.5 mL of 0.207 M calcium acetate?

0 ⤊

How much grams of solute in 168.5 mL of 0.207 M calcium acetate?

Molecular Weight of Ca(C2H3O2)2=158.188

2006-09-24 15:56:59 · 1 answers · asked by julie_cha06 1 in Education & Reference ➔ Homework Help

1 answers

Molarity = moles/liter
Thus, moles = Molarity * Volume
Moles = .1685 L * .207 = 0.0348795

Since you already have the molecular weight, the # of grams = moles * molecular weight
# of grams = 0.0348795 * 158.188 = 5.52 g (solution!)

2006-09-25 01:41:41 · answer #1 · answered by ³√carthagebrujah 6 · 0⤊ 0⤋