If the some of the measures of 2 angles is 90 degrees, the angles are complementary. Thus, if the measure of?

Question

an angle is A^degrees, the measure of the complement is (90-A)^degrees. Find an angle whose measure is 3 greater than twice the measure of its complement.
(Please show your work. Thank you!)

Answer 1

A + (90-A) = 90

3A = 3(2(90-A)) divide both sides of the equation by 3

A = 2(90-A) = 180 - 2A add 2A to both sides of the equation

3A = 180 divide both sides of the equation by 3

A = 60
Ac = 90 -60 = 30
3(2(30)) = 180

Of course it depends on how you read your question.
If you are saying that:
3(2(90-A))=A then
3(180-2A) = A
540 - 6A = A
540 = 7A
A = 77.14 and
Ac = 90 - A = 90-77.14 =12.86

Your answer in this case is 77.14 degrees
Of course if it is simply +3 degrees you meant than
2(90-A) + 3 = A
180-2A+ 3 = A
183 = 3A
A = 183/3 = 61

Answer 2

2x+3+x=90
3x+3=90 (lowest commom term)
x+1=30

then x =29
your two angles are 29 and 61

Answer 3

the two equations you will get is x+9 and 2x. via fact it says "9 greater" and "two times the different" set it up as x+9+2x=ninety. combine like words and then subtract 9 from the two factors and you gets 3x=80 one that's 27. then you definitely plug the 27 lower back into the two unique equations. 27+9=36, 27x2=fifty 4, upload their sums at the same time and you get ninety.

Answer 4

After seeing at least 7 of your math questions on Yahoo!Answers, I have a question for you. Why are you asking other people to do your work for you? Just curious.