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integers were three in number and were such that 5 times the sum of the first and third was 108 greater than twice the opposite of the second. What were the integers?
(Please show your work because according to my book, the answer is 7,9,and 11. Thank you!)

2006-09-24 15:24:59 · 2 answers · asked by Chelsey 5 in Education & Reference Homework Help

2 answers

let x = the first integer. Then the other two are x+2 and x+4.
So according to the problem,
5(x + x + 4) - 108 = 2(-(x+2))
You do the rest

2006-09-24 15:36:11 · answer #1 · answered by banjuja58 4 · 0 0

The answer is correct. Just right the numbers down just as it says. The only difficulty is the "opposite" reference. It means the second number would be changed to a negative in this case.

Try it.

2006-09-24 22:35:49 · answer #2 · answered by SPLATT 7 · 0 0

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