2006-09-24 14:57:28 · 9 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Multiply both sides by k+3.
Now you have
6-2k=4k+12
Can you solve it from there?
2006-09-24 15:00:37 · answer #1 · answered by just♪wondering 7 · 0⤊ 0⤋
K= -1
2006-09-24 22:00:28 · answer #2 · answered by Bob 1 · 0⤊ 1⤋
k= -1
2006-09-24 22:03:43 · answer #3 · answered by Dave 4 · 0⤊ 0⤋
k = -1
multiply by denominator on both sides
6-2k = 4(k+3)
6-2k = 4k+12
6 = 6k+12
-6 = 6k
-1 = k
2006-09-24 22:01:36 · answer #4 · answered by bossmanham 2 · 0⤊ 0⤋
(6 - 2k) / (k + 3) = 4
6 - 2k = 4(k+3) = 4k + 12
6 - 12 = 4k + 2k
-6 = 6k
k = -1
2006-09-24 22:02:03 · answer #5 · answered by daylightpirate 3 · 0⤊ 0⤋
2k+k=6+3+4
3k =15
k =15/3
k =5
What u did is to group the like terms,and add the k to the two and u get 3k and then add the numbers by themself and we got 15 the the 3 go over and turn to division and divided the 15 by the 3 and we found k to be 5.
GGODLUCK.
2006-09-24 22:08:16 · answer #6 · answered by daisey_beauty2004 1 · 0⤊ 0⤋
6-2k=4(k+3)
6-2k=4k+12
-2k-4k=12-6
-6k=6
k=-1
2006-09-24 22:02:52 · answer #7 · answered by iyiogrenci 6 · 0⤊ 0⤋
lol u must be in like 6th grade or sometin
k= -1.. property of equality w/e vote me as best answer cuz im special..
2006-09-24 22:06:28 · answer #8 · answered by Mr.Deeds 5 · 0⤊ 0⤋
Here's a hint to get you started...
Multiply both sides by the denominator.
2006-09-24 22:01:19 · answer #9 · answered by Anonymous · 0⤊ 0⤋