The greater of 2 consecutive even integers is 10 less than twice the smaller. Find the integers? this is so confusing!
2006-09-24 13:24:58 · 4 answers · asked by eatitnow21 1 in Education & Reference ➔ Homework Help
EDIT: THIS IS THE CORRECT ANSWER!!!
The greater of 2 consecutive even integers is 10 less than twice the smaller. Find the integers.
Let x = the smaller integer.
Let x + 2 = the larger integer.
So, the larger integer + 10 = 2 times the smaller integer, right?
Convert the words to a formula:
x + 2 = 2x -10
Rewrite the equation with the 2x on the left side and solve for x:
2x -10 = x + 2
2x - x = 2 + 10
x = 12 (The smaller integer)
Answer:
Smaller integer = 12
Larger integer = 14
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**Always** check your answer.
Larger integer (14) = 2 * 12 - 10
x + 2 = 2x -10
(12 + 2) = [(2 * 12) -10]
14 = 14 <== checks!
Good luck in your class.
2006-09-24 15:58:47 · answer #1 · answered by Mitch 7 · 0⤊ 0⤋
Let the integers = x and x+2.
2x = x+2 + 10
x = 12
x + 2 = 14
2006-09-24 20:28:57 · answer #2 · answered by gburgmommy 3 · 0⤊ 0⤋
the answers are 11 and 12.
11 * 2 = 22
22 - 10 = 12
2006-09-24 20:30:16 · answer #3 · answered by chocolahoma 7 · 0⤊ 1⤋
A = 2B - 10, A = B+1
B+1 = 2B - 10
B = 2B - 11
B - 2B = -11
-B = -11
B = 11
(12) = 2(11) - 10 b/c A = B +1 = 12
12 = 22 - 10
12 = 12
it checks out
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2006-09-24 20:35:56 · answer #4 · answered by Lobster Dinosaur 3 · 0⤊ 1⤋