:N(3bonds)C(1bond)O:::(-) <------> ?
(: means 1 long pair, ::: means 3 long pairs, (-) negative charge, and there are two errous one from 3 bonds going to N, the othere one from O going to C, errous shows electron pair movements
A) ::N(-)=C=O::
B) ::N(-)=C-O::
C)::N(-)(3bonds)C=O::
D)::N(-)=C=O:::
I was thinking it is A, but my friend says it is B. We to find who is right.
2006-09-24 11:54:47 · 5 answers · asked by marinagg 1 in Science & Mathematics ➔ Chemistry
You're right. Count the electrons; A has 16, and B has 14. C (4) + N (5) + O (6) + 1 extra is 16. C has too many electrons on the N, and D has too many electrons on the O.
2006-09-24 12:10:53 · answer #1 · answered by Mr. E 5 · 0⤊ 0⤋
You have to produce octets, which means they need a total of 8 dots around them (electrons) and one little "-" is equal to 2. So if you count the ones on b the carbon and oxygen don't have an octect because they only have 6 dots (electrons). c has way to many bonds on the nitrogen and d has to many on the oxygen so a is correct.
2006-09-24 12:18:01 · answer #2 · answered by angeliquedesjardins 3 · 0⤊ 0⤋
The answer is A, answer B is missing two electrons.
2006-09-24 12:04:14 · answer #3 · answered by Gnothi Seauton 1 · 0⤊ 0⤋
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2016-10-17 21:58:31 · answer #4 · answered by ? 4 · 0⤊ 0⤋
I pick B
2006-09-24 11:57:47 · answer #5 · answered by ecogeek4ever 6 · 0⤊ 0⤋