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the math question is: -6*3+(4*(-5)+7)/3(4-1) please show all your work--ive tried this problem many times and always get a different answer

2006-09-24 11:25:47 · 3 answers · asked by Anonymous in Education & Reference Homework Help

the math question is: -6*3+(4*(-5)+7)/3(4-1) please show all your work--ive tried this problem many times and always get a different answer---my work is this

-6*3+(4*(-5)+7)/3(4-1)
-6*3+(-13)/3*3
-18+(-13)/3*3
-18+(-4.3(repeating))*3
-18+(-13)
=5

2006-09-24 11:37:43 · update #1

3 answers

-6*3+(4*(-5)+7)/3(4-1)
-18+(4*(-5)+7)/3(4-1)
-18+(-20+7)/3(4-1)
-18+(-13)/3(4-1)
-18+(-13)/3(3)
-18+(-13) ←Yes, this is correct. See below.
-31

Multiplication and division have the same priority, so we evaluate them from left to right - i.e. divide 13 by 3 then multiply 13/3 by 3, not multiply 3 by 3 and then divie 13 by 9. The fact that the multiplication is written implicitly does not change this.

Edit: Your order of operations is correct. The problem is that at the end, you are computing 18+(-13), not -18+(-13), which is what you actually have written.

2006-09-24 11:38:29 · answer #1 · answered by Pascal 7 · 0 0

What is the numerator? Is it all of the first part [-6*3+(4*(-5)+7)], or just (4*(-5)+7)? I'll be happy to help if you give me more info. :)

2006-09-24 18:38:27 · answer #2 · answered by killingwish 4 · 0 0

You have to make sure you follow the correct order of operations.

Please (parentheses)
Excuse (exponents)
My Dear (multiplication/division)
Aunt Sally (addition/subtraction)

YOU show YOUR work so we can see where you're doing it wrong.

a negative plus a negative is always a negative...

2006-09-24 18:28:55 · answer #3 · answered by Anonymous · 0 0

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