Say you have a rope...on one end a force of 50 N is applied, on the other a force of 20 N. I know that this will cause acceleration in the direction of the 50 N force...but what is the tension in the rope??
2006-09-24 09:49:42 · 4 answers · asked by acm11216 2 in Science & Mathematics ➔ Physics
Kinda depends on what's holding them up, if anything. If they're in free fall, 0 N. If hung by the 20 N weight, 50 N. If hung by the 50 N weight, 20 N. If hung from the middle with no pulley, 20 N on one side, 50 N on the other. If hung by a pulley in the middle, 28.57 N. This last is the solution F to:
acceleration1 = -acceleration 2
acceleration 1 (in g) = -1 + F/20
acceleration 2 (in g) = -1 + F/50
-1 + F/20 = 1 - F/50
The weights accelerate (in opposite directions) at 0.4286 g.
EDIT: It can't be the difference: if the weights are equal you'd have no force. It can't be the sum: the force is the same throughout the rope, and 70 N would be raising both weights.
2006-09-24 10:49:26 · answer #1 · answered by kirchwey 7 · 0⤊ 1⤋
If you are ignoring the mass of the rope then the tension is the difference between the forces which is 30N. If not ignoring the mass of the rope the tension varies from one end to the other.
2006-09-24 17:58:54 · answer #2 · answered by Demiurge42 7 · 0⤊ 0⤋
70 N
2006-09-24 16:52:32 · answer #3 · answered by pump_runner 2 · 0⤊ 1⤋
tricky problem. browse on google. it will help!
2014-11-07 00:19:12 · answer #4 · answered by Anonymous · 0⤊ 0⤋