Confused on a physics problem...?

Question

Ok, here's the problem...

"If 50 grams of hot water at 80degrees celsius is poured into a cavity in a very large block of ice at 0 degrees celsius, what will be the final temperature of the water in the cavity? How much ice must melt in order to cool the hot water down to this temperature?"

How do I go about finding this answer? Am I supposed to use Q = mcDT?

Answer 1

Let the amount of ice melted be x grams.
Heat taken by x grams of ice to melt = ( latent heat of ice )*x cal
=80x
Heat lost by 50 grams of water to come from 80 degrees Celsius to zero degree Celsius
= (mass of water)*(specific heat of water)*(change in temperature)
=50*1*80=4000 calories
Thus we have
80x=4000
or
x=4000/80=50grams
And the final temperature of water will be zero degrees Celsius.

Answer 2

Everyone is taking this problem as too complicated. If the block of ice is big enough the water will cool and melt ice until the water is 0 degrees C. Isn't that simpler?

Answer 3

This is a question on SLH and fusion

Answer 4

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