If p varies jointly with q and the square of r,& p is 864 when q is 6 and r is 4,find p when q is 8 and r is 5

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If p varies jointly with q and the square of r,& p is 864 when q is 6 and r is 4,find p when q is 8 and r is 5

I can't figure out how to get the answer for this constant of proportionality. HELP !!!

2006-09-24 08:23:42 · 1 answers · asked by heather d 2 in Science & Mathematics ➔ Mathematics

1 answers

Let k be your constant of proportionality. Then:
p=kqr²
Substitute the first set of values:
864=k*6*16
k=9
Having found k, substitute the second set of values:
p=9*8*25
p=1800

2006-09-24 08:29:27 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋