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FIND THE MEASURES OF ALL THREE ANGLES.

PLEASE HELP!

2006-09-24 08:16:44 · 8 answers · asked by Lizzie101 2 in Education & Reference Homework Help

8 answers

impossible

2006-09-24 08:18:17 · answer #1 · answered by ĵōē¥ → đ 6 · 1 0

Smallest Angle:1/2x (smallest angle is 1/2 as large as the largest)
Middle Angle:1/4x (the smallest angle is twice the third)
Largest Angle: x (don't know the largest)

All three angles of a triangle add to 180 degrees. So 1/2x + 1/4x + x = 180.

If you wrote out the problem wrong this equations won't work.

Hope this helps. Good Lick.

2006-09-24 08:26:09 · answer #2 · answered by SmileyGirl 4 · 0 0

let the largest angle = x the smallest angle will be = 1/5x The third angle will be = 2/5x x + 1/5x + 2/5x = 180 degrees x = 112.5 1/5x = 22.5 2/5x = 45

2016-03-27 07:25:38 · answer #3 · answered by Anonymous · 0 0

X = smallest angle
2X = largest angle
.5X = third angle

The sum of angles of every triangle is 180 degrees, so
X + 2X + .5X = 180
3.5 X = 180
X = 180/3.5

2006-09-24 08:43:46 · answer #4 · answered by saddlesore 3 · 0 0

how can the smallest angle be twice as large as the third angle if it is the smallest angle?

2006-09-24 08:25:29 · answer #5 · answered by Forest_aude 3 · 0 0

A=1/2B
A=2C
A+B+C=180
2A-B=0
adding
3A+C=180
A-2C=0
3A-6C=0
7C=180
C=180/7
A=360/7
B=720/7

2006-09-24 08:27:47 · answer #6 · answered by raj 7 · 0 0

30 60 90

180=1x+(1/2)x+(3/2)x

x=60

2006-09-24 08:26:54 · answer #7 · answered by sangreal 4 · 0 0

think your teacher might have been thinking of curved space.
or mayybe it's copied wrong?

2006-09-24 08:29:08 · answer #8 · answered by Mose F 1 · 0 0

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