The 2 vectors 3i-7j (no k) and 2i+3j-2k define a plane (its the plane of the triangle with both tails at one vertex and each head at one of the other vertices).
Which of the following vectors is perpendicular to the plane?
a 4i+6j+13k
b -4i+6j+13k
c 4i-6j+13k
d 4i+6j-13k
e 4i+6j
I did the cross product and got
=i(AyBk-AkBy)+j(AkBx-AxBk)+k(A...
=14i+6j+23k
How do I go from here?
2006-09-24 08:15:50 · 3 answers · asked by dutchess 2 in Science & Mathematics ➔ Physics
(I often also post my questions in the general math section in order to get more people to answer them.)
2006-09-24 09:46:31 · update #1
Okay, is there some kind of reason why you have to ask every single one of your questions twice?
http://answers.yahoo.com/question/index;_ylt=AvjFrO0yK4P79FV6JfJlUj7sy6IX?qid=20060924110938AACcjo9
2006-09-24 08:54:09 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
So is that vector parallel to any of the answers? You could try taking the cross product with each of the answers.
2006-09-24 15:24:05 · answer #2 · answered by cosmo 7 · 0⤊ 0⤋
do dot product, cos a.b=a*b*cos(angle)
that should come to zero....
2006-09-24 15:25:16 · answer #3 · answered by ashwin_hariharan 3 · 0⤊ 0⤋