28
2006-09-24 07:41:25
·
answer #1
·
answered by Matthew L 2
·
1⤊
0⤋
There can only be one HIGHEST common factor as it is the highest of all the factors that are common to the two numbers.
56 has the following factors: 1, 2, 4, 7, 8, 14, 28, 56
84 has the following factors: 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84
The common factors are: 1, 2, 4, 7, 14, 28
So the highest common factor is 28.
2006-09-24 12:04:37
·
answer #2
·
answered by Kemmy 6
·
0⤊
0⤋
Write out all the factors of both numbers and then look for the biggest number that appears in both lists.
56 = {1, 2, 4, 7, 8, 14, 28, 56}
84 = {1, 2, 3, 4, 6, 7, 12, 14, 26, 42, 84}
14 is the biggest number so it is the highest common factor
2006-09-24 07:54:18
·
answer #3
·
answered by JuJu 3
·
0⤊
0⤋
Rather than writing out all the factors express each number as a product of primes.
56 = 2 * 2 * 2 * 7
84 = 2 * 2 * 3 * 7
The common primes are 2 * 2 * 7 = 28
2006-09-25 03:01:37
·
answer #4
·
answered by tringyokel 6
·
0⤊
0⤋
56 84 2*
28 42 2*
14 21 2
7 21 3
7 3 3
7 1 7
Answer=2*2=4
2006-09-24 07:43:12
·
answer #5
·
answered by iyiogrenci 6
·
0⤊
1⤋
28*2=56
28*3=84
so 28 is the answer
2006-09-24 07:43:48
·
answer #6
·
answered by raj 7
·
1⤊
0⤋
28
2006-09-24 08:19:32
·
answer #7
·
answered by martin n 1
·
0⤊
0⤋
28
2006-09-24 07:47:35
·
answer #8
·
answered by Anonymous
·
0⤊
0⤋
28
2006-09-24 07:46:06
·
answer #9
·
answered by ? 7
·
0⤊
0⤋
the factors of 56 are
1,2,4,7,8, 14,28, 56
the factors of 84 are
1,2,3,4,6,7, 12,14,21, 28, 42, and 84.
the highest number that is in both of those sets is
28
2006-09-24 07:53:39
·
answer #10
·
answered by blahhhaha 3
·
1⤊
0⤋