how do you do this problem?
A hockey team played n games, losing four of them and winning the rest. The ratio of games won to games lost is?
2006-09-24 07:33:31 · 12 answers · asked by princesschristine91 1 in Science & Mathematics ➔ Mathematics
games played: n
games lost: 4
games won: n - 4
games won / games lost = (n - 4) / 4
2006-09-24 07:43:40 · answer #1 · answered by Deep Thought 5 · 1⤊ 0⤋
N games in total. They won N - 4 games. The ratio of won to lost is N-4 to 4.
2006-09-24 14:39:05 · answer #2 · answered by Luscious L 1 · 1⤊ 0⤋
To figure this out, you take n games. since you know you have lost 4 of the games, you would write that as 4/n using x as the games won, you would write that as x/n so, the ratio would be x/n:4/n
Granted, I haven't done this type of math in years, but from what I can remember this would be the correct way of figuring it out. Hope this helps.
2006-09-24 14:38:53 · answer #3 · answered by Genny 3 · 0⤊ 1⤋
n:4 n=how many games are won
4=how many games lost
2006-09-24 14:42:17 · answer #4 · answered by //.S M ii L E S 2 · 0⤊ 1⤋
n - 4 : 4
2006-09-24 14:40:13 · answer #5 · answered by Hopeful Poster 3 · 2⤊ 0⤋
n-4/n
2006-09-24 14:38:42 · answer #6 · answered by class4 5 · 0⤊ 1⤋
(n/4)-1
2006-09-24 15:06:00 · answer #7 · answered by ? 7 · 0⤊ 1⤋
-4-n
2006-09-24 14:43:56 · answer #8 · answered by Anonymous · 0⤊ 2⤋
(n-4)/n
2006-09-24 14:42:48 · answer #9 · answered by bruinfan 7 · 0⤊ 1⤋
(n-4):4
2006-09-24 14:37:13 · answer #10 · answered by raj 7 · 1⤊ 1⤋