solving trig identies?

Question

I have absolutely no idea how to solve this...

It says use trig identities to transform one side of the equation into the other.

(tan(beta)+cot(beta))/tan(beta)=csc^2(beta)


Can anyone help me with this?! This is 11th grade honors trig.

forget the problem up there...i dont remember even typing that...sorry

This is the problem

(tan(beta)+cot(beta)/tan(beta)=csc^2(beta)

ok i wrote the problem, but it put in the (...) trust me its getting annoying

where it says ..., that is the = sign.
so, =csc^2

Answer 1

the sum is incomplete.can you give the entire sum?

Answer 2

sure - you're on route yet no longer extremely perfect. sqrt(2)/2 = a million/sqrt(2) so, A isn't pi/6, yet pi/4 in case you draw an isosceles triangle with the perimeters = a million and the attitude between being pi/2, you'll locate that the hypotenuse is sqrt(2). So, the cosine of the attitude = a million/sqrt(2) ( or sqrt(2)/2)

Answer 3

you said that you have to transform one side of the equation to the other, but what's the complete equation? you only gave part of it.

Answer 4

tan(beta)+cot(beta)/tan(beta)
= tan(beta)+ 1/ tan(beta)
.........................................
tan(beta)
=tan^2(beta)+1
..........................
tan(beta)
= sec^2(beta)/tan(beta)
= 1/cos^2(beta) x1/sin(beta)/cos(beta)
= 1xCos(beta)
.......................
cos^2(beta)xsin(beta)
= 1/cos(beta)xsin(beta)
= sec(beta)x cosec(beta)
if you have written this question right then above is answer.
try to use pen tablet to write such questions, it saves time and its fast working.