29.
The product of two consecutive positive even integers is 360. Find the integers.
2006-09-24 07:10:02 · 4 answers · asked by pjaxdriver13 1 in Science & Mathematics ➔ Mathematics
20 and18
working out
n(n+2)=360
n^2+2n-360=0
n^2+20-18-360=0
n(n+20)-18(n+20)=0
(n+20)(n-18)=0
n=-20 or +18
so the nos are 20 and 18 or -18 and -20
2006-09-24 07:14:59 · answer #1 · answered by raj 7 · 1⤊ 0⤋
let
x = the first consecutive even integer
x + 2 = The second consecutive even integer
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x(x + 2) = 360
x(x + 2) - 360 = 0
x² + 2x - 360 = 0
(x + 20)(x - 18)
x = - 20 or x = 18
The integers are 18 and - 20
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Check
x = - 20
x(x + 2) = 360
- 20(-20 + 2) = 260
- 20 (- 18) = 360
360 = 360
- - - - - - - - - - - - - - -
Check
x = 18
x(x + 2) = 360
18(18 + 2) = 360
18(20) = 360
360 = 360
2006-09-24 07:40:27 · answer #2 · answered by SAMUEL D 7 · 0⤊ 0⤋
The answer is 18 X 20 But I could not figure it out using algerbra as my Algerbra is very rusty... I thoing you would set it up as below:
X x(X+2) = 360
I hope this helps...
2006-09-24 07:26:32 · answer #3 · answered by arnp4u 3 · 0⤊ 0⤋
18 and 20
18x20=360
good luck
2006-09-24 07:18:08 · answer #4 · answered by Simplystunning 4 · 0⤊ 0⤋