An object is dropped from rest and falls freely. After 6 seconds, Calculate the instantaneous speed, average speed and distance fallen?
2006-09-24 05:53:52 · 14 answers · asked by Hamza 1 in Science & Mathematics ➔ Physics
You should do your homework yourself!
2006-09-24 05:56:23 · answer #1 · answered by mystique_dragon4 4 · 0⤊ 0⤋
Instantaneous speed: acceleration x time (g*6)
Distance fallen: ½at²
average speed: distance fallen/ 6 seconds.
2006-09-24 13:03:38 · answer #2 · answered by dane 4 · 0⤊ 1⤋
yeah ok, what was the question? Every object is going to have a different instantaneous speed, average speed and distance fallen.
2006-09-24 12:56:27 · answer #3 · answered by Juicy Fruit 4 · 0⤊ 1⤋
Equations for a falling body
Main article: Equations for a falling body
Under normal earth-bound conditions, when objects move owing to a constant gravitational force a set of kinematical and dynamical equations describe the resultant trajectories. For example, Newton’s law of gravitation simplifies to F = mg, where m is the mass of the body. This assumption is reasonable for objects falling to earth over the relatively short vertical distances of our everyday experience, but is very much untrue over larger distances, such as spacecraft trajectories, because the acceleration far from the surface of the Earth will not in general be g. A further example is the expression that we use for the calculation of potential energy of a body = mgh. This expression can be used only over small distances from the earth. Similarly the expression for the maximum height reached by a vertically projected body,"h = u^2/2g " is useful for small heights and small initial velocities only. In case of large initial velocities we have to use the principle of conservation of energy to find the maximum height reached.
2006-09-24 13:01:22 · answer #4 · answered by Patrick 2 · 0⤊ 1⤋
velocity at 6th second is its instataneous velocity which is given by the formula
v = g x t =9.8 m/s^2 x 6 .0 s = 59 m/s Its initial velocity is 0 m/s.
Av. vel is the average of initial and final velocities.whicxh is 30 m/s
dis. = 0.5 x g x t ^2 = 176 m
2006-09-24 13:06:48 · answer #5 · answered by Dinker 2 · 0⤊ 1⤋
speed = intial velocity( which is 0 since you dropped it) + accelerationxtime
average speed= distance fallen/time
distance fallen = 1/2accelerationxtime^2
2006-09-24 12:59:49 · answer #6 · answered by Greg G 5 · 0⤊ 1⤋
you havent given the mass if we consider it as (m) then distance fallen(d)=velocity(v)/6
instantaneous speed = d/36. average speed= total distance/total time
Next time give more description
2006-09-24 13:13:22 · answer #7 · answered by Akshay p 2 · 0⤊ 0⤋
Speed= 9.8*6=58.8m/s
Average speed= 9.8m/s
distance fallen= .5*9.8*36=176.4 m
2006-09-24 12:59:17 · answer #8 · answered by bruinfan 7 · 0⤊ 1⤋
How can THAT be answered? You don't give us the speed and the weight.
2006-09-24 12:57:57 · answer #9 · answered by TNT 2 · 0⤊ 0⤋
instanteneous speed= v=u+at
av speed=u+v/2
s=ut+1/2at^2
2006-09-24 13:11:26 · answer #10 · answered by happygirl 2 · 0⤊ 0⤋
Oops Sorry.
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2006-09-24 13:02:45 · answer #11 · answered by ~Nan oru Naai~ 1 · 1⤊ 0⤋