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Given that

lim ... f(x) = B, then lim {3[f(x)]^2 + 4f(x) - 2B^2 - 3B} =
x=>a .................... x=>a

2006-09-24 05:48:48 · 2 answers · asked by Olivia 4 in Science & Mathematics Mathematics

2 answers

=3B^2+4B-2B^2-3B
=B^2+B

2006-09-25 02:20:49 · answer #1 · answered by Anonymous · 0 1

Limit operator is a linear operator, so we can use this property to analyze the above expression.

limit === 3 lim(f(x))^2 + 4 lim(f(x)) - 2B^2 - 3B

(limit of a constant = constant)

= 3B^2 + 4B - 2B^2 - 3B

= B^2 + B

or the limit (x goes to a) == B(B+1)

2006-09-24 05:57:41 · answer #2 · answered by alrivera_1 4 · 1 0

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