Vera's piggy bank contained $9.35 in quarters, dimes and nickels. There were six more than two times as many nickels as quarters and four less dimes than quarters. How many of each kind of coin was there in the bank?
I will best answer the person who gives me an explanation along with the correct answer. Thank you so much!
2006-09-24 05:46:25 · 2 answers · asked by Katt Attack 3 in Science & Mathematics ➔ Mathematics
N = 2*Q + 6,
D = Q - 4
5*N + 10*D + 25*Q = 935,
5*(2Q+6) + 10*(Q-4) + 25*Q = 935,
45*Q = 945,
Q=21, D=17, N=48
2006-09-24 05:57:59 · answer #1 · answered by Joe C 3 · 0⤊ 0⤋
x=quarters y=dimes z=nickels
.25x+.1y+.05z = 9.35
2x+6=z......2x-z=-6
x-4=y.....x-y=4
you can solve algebraicly(substitution, elimination, etc) or use a matrix.
either way you get
x=21
y=17
z=48
2006-09-24 12:55:14 · answer #2 · answered by Greg G 5 · 0⤊ 0⤋