Can this be differentiated? i tried but got 0 as the numerator. The curve y= (2x+1) / (2x-1)... Please help, points up for grabs.
2006-09-24 05:39:19 · 13 answers · asked by Anonymous in Education & Reference ➔ Homework Help
The derivative of this equation would be 0.
If you have a TI-83 (or higher, or plus), you can go to y= and plug in the equation y=(2x+1)/(2x-1) and then press SECOND TRACE. Go down to number 6 and then press Enter. Press enter again and again and then it will show you the DX/DY as 0
2006-09-24 05:40:18 · answer #1 · answered by ĵōē¥ → đ 6 · 1⤊ 0⤋
If you work it out, it comes to y=4x^2-1. Plug in 0 for x. You get y=-1, so the point where it crosses the y axis is (0,-1). Then plug in points like -2,-1,1, and 2 for x to get your values. Good luck!
2006-09-24 12:43:03 · answer #2 · answered by knifelvr 4 · 0⤊ 0⤋
answer is 0
if its 2x+1/2x+1 the answer is 1
2006-09-24 12:43:08 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The answer is:
-4 / (2x - 1)^2
If you are having problems, you should speak to your teacher who will be able to sit down and go through these problems with you.
2006-09-24 13:22:04 · answer #4 · answered by Andrew W 4 · 0⤊ 0⤋
y= 2x+1/ 2x - 1
dy/dx = (vdu/dx - udv/dx)/ v^2
with u = the top bit and v = the bottom.
=((4x-2) - (4x + 2))/ (2x-1)^2
= - 4/(2x - 1)^2
i think thats right but im not sure if i remembered the formula correctly
2006-09-27 14:52:52 · answer #5 · answered by narglar 2 · 0⤊ 0⤋
yes. check your calculation again carefully if u have mixed up any plus or minus sign. i think the answer will be:
dy/dx = -4 / (2x-1)^2
2006-09-24 12:50:56 · answer #6 · answered by yk1982 2 · 0⤊ 0⤋
the differential is
..
[2(2x-1)-2(2x+1)] / (2x-1)^2
=-4 / (2x-1)^2
...
the formula is
d(u/v) = [vdu - udv]/v^2
..
^2 is squared
2006-09-24 12:55:47 · answer #7 · answered by sunil 3 · 0⤊ 0⤋
This is the best web site for maths going!
Especially the step by step solution section
2006-09-26 16:58:43 · answer #8 · answered by JuJu 3 · 0⤊ 0⤋
Can I get back to you later on this only the kids have been playing with my abacus again & I cant find it anywhere!
2006-09-24 12:48:37 · answer #9 · answered by Anonymous · 0⤊ 0⤋
no because the positive cancels out the negative
2006-09-24 12:43:01 · answer #10 · answered by Veronica 1 · 0⤊ 0⤋