1.) A 95-meter long train begins uniform acceleration from rest. The front of the train has a speed of 25 meter/second when it passes a railway worker who is standing 180 m from wherer the front of the train started. What will be the speed of the last car as it passes the worker.
2006-09-24 05:06:14 · 3 answers · asked by micheal j 1 in Science & Mathematics ➔ Physics
Well, you know v1=0, and v2=25. So you can calculate acceleration over that first distance (180 meters).
Then, do the same thing, this time using v1=25 and v2=x, you know acceleration, and you know distance (95 meters, because that's how far the train has to travel for the whole thing to get past the railway worker).
2006-09-24 05:14:49 · answer #1 · answered by Brian L 7 · 0⤊ 0⤋
I sure hope it's 25, otherwise the train will be squished.
2006-09-24 12:33:11 · answer #2 · answered by felix_doc 2 · 1⤊ 0⤋
36.5 meters/second
2006-09-24 12:15:25 · answer #3 · answered by Anonymous · 0⤊ 0⤋