Please Simplify: (x^2y^-3 z)^1/2 divided by x^1/2y z^-1/2?

0 ⤊

Please show steps.

2006-09-24 05:03:17 · 2 answers · asked by Paul B 1 in Science & Mathematics ➔ Mathematics

[(x^2 y^-3 z)^1/2] / [x^1/2 y z^-1/2]
=
[x^1 y^-3/2 z^1/2] / [x^1/2 y z^-1/2]
=
[x^1/2 y^-5/2 z^1]
=
x^(1/2) z / y^(5/2)
OR
z sqrt(x / y^5)

2006-09-25 08:22:56 · answer #1 · answered by dutch_prof 4 · 0⤊ 0⤋

(x^2y^-3 z)^1/2 divided by x^1/2y z^-1

= ((X^2y^-3z^2/XY^2))^1/2

=(XY^-5Z^2)1/2

=X^(1/2)Y^(-5/2)Z

2006-09-24 12:16:38 · answer #2 · answered by Pradyumna N 2 · 0⤊ 0⤋