Trigonometric Integration - Step by step
2006-09-24 05:01:57 · 4 answers · asked by thegame1083 1 in Science & Mathematics ➔ Mathematics
Hi Robert
∫√(x^2 - 9) /x dx =
√(-9 + x^2) + 3 Arc Tan(3 / √(9 + x^2)) + c
It's the correct answer.
Good Luck
2006-09-25 09:34:53 · answer #1 · answered by sweetie 5 · 2⤊ 0⤋
let x^2-9 =t
differentiating both sides
2xdx = dt
now int(sqrt(x^2-9) x dx)
= int(sqrt t*(1/2) dt/2
= t^(-1/2)/(-1/2)/2
= -t^(-1/2)
= -1/t^(1/2)
= -1/(x^2-9)^(1/2)
2006-09-24 12:08:24 · answer #2 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
let x^2= t
2xdx=dt
xdx=1/2. dt
finish by yourself
2006-09-24 12:04:59 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋
xdx/(x^2-9)^1/2
put x^2-9=t
2xdx=dt
xdx=1/2dt
integral=dt/(2rt t)
(1/2)(-1/2)t^-3/2+c
-1/(4t^3/2)+C
-1/4(x^2-9)^3/2 +C
2006-09-24 12:07:07 · answer #4 · answered by raj 7 · 0⤊ 0⤋