Q:
Lim .......... 2^1/x =
x=>0-
2006-09-24 04:55:19 · 6 answers · asked by chris 2 in Science & Mathematics ➔ Mathematics
If x goes to 0 from the left, then 1/x goes to -infty. Now what happens to 2^(1/x) as 1/x goes to -infty? It does *not* go to -infty! In fact, it goes to 0.
2006-09-24 04:59:26 · answer #1 · answered by mathematician 7 · 1⤊ 0⤋
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2016-11-23 19:04:41 · answer #2 · answered by Anonymous · 0⤊ 0⤋
x->0 2^(1/x) let it be y
log y = 1/x log 2
as x->0-
log y -> - infinite
so y-> e^-(inf) = 0
what is the solution in the book
2006-09-24 05:03:39 · answer #3 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
It would be 2 raised to a really big number, which wouldn't be negative.
2006-09-24 05:01:50 · answer #4 · answered by felix_doc 2 · 0⤊ 0⤋
email me the name of the book
2006-09-24 04:58:05 · answer #5 · answered by Raymond B 4 · 0⤊ 0⤋
You tell us
2006-09-24 04:56:39 · answer #6 · answered by Anonymous · 0⤊ 2⤋