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how do i find the inverse of f(x) = 1/x + 2

show the steps i am so confused on how to get it!

2006-09-24 04:52:38 · 3 answers · asked by abbs 2 in Science & Mathematics Mathematics

3 answers

1/f(x) = 1 / [1/x+2]
multiply by x above and below
1/f(x) = x / [ x/x+2x ]
1/f(x) = x / [ 1+2x ]
you can also do a polynomial division ...
divide by 2 above and below
1/f(x) = (1/2) x / [ 1/2+x ]
1/f(x) = (1/2) [ x +1/2-1/2 ] / [ 1/2+x ]
1/f(x) = 1/2 - (1/4) / [ 1/2+x ]
finally 1/f(x) = 1/2 - 1 / [ 2+4x ]

2006-09-24 05:00:41 · answer #1 · answered by sebourban 4 · 0 0

Interchange the x and y. An inverse function is the mirror image of the original function.


y= 1/x + 2

becomes,
x= 1/y + 2

Then rearrange to make it neater, usually they prefer general solutions for final answer.

2006-09-24 11:54:59 · answer #2 · answered by Anonymous · 0 0

First, get rid of the fractional term; so you have (1 + 2x)/x.

Then invert f(x) = (1 + 2x)/x by cross multiplying the denominators and numerators.

2006-09-24 11:59:44 · answer #3 · answered by oldprof 7 · 0 0

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