Let f(x) = 3x^2 + 8x + 4 and g(x) = 4x^2 + 7x - 2 .
Then
lim ............. f(x)/g(x) =
x=>-2
2006-09-24 04:44:32 · 6 answers · asked by chris 2 in Science & Mathematics ➔ Mathematics
limx>-2 (x+2)(3x+2)/(4x-1) (x+2)
-4/-9=4/9
2006-09-24 04:52:19 · answer #1 · answered by raj 7 · 1⤊ 0⤋
The ratio f(x)/g(x) is in the form 0/0. So the required limit is the limit of the ratio of the derivatives of the functions :
lim.....(6x + 8) / (8x + 7) = (8 - 12) / (7 - 16) = 4/9
x=>-2
2006-09-24 11:56:44 · answer #2 · answered by Problem Child 2 · 1⤊ 0⤋
not correct
0/0
using hospital rule
6x+8 over 8x+7
-12+8 or -16+7
answer: -4/-9 or 4/9
2006-09-24 11:51:37 · answer #3 · answered by iyiogrenci 6 · 1⤊ 0⤋
f(x) = (3x+2)(x+2)
g(x) = (4x-1)(x+2)
(x+2) term cancels
answer 7/9
since you can factor it to avoid the zero in
denominator, I'm not sure if l'Hopital's rule applies
2006-09-24 11:57:50 · answer #4 · answered by banjuja58 4 · 0⤊ 0⤋
7/9 also ! Good Luck ! :)
2006-09-24 11:46:10 · answer #5 · answered by tysavage2001 6 · 0⤊ 0⤋
my brain hurts
2006-09-24 12:06:23 · answer #6 · answered by neil d 3 · 0⤊ 0⤋