lim ........... (x^2 - x - 6)/(x^2 - 9) =
x=>3
2006-09-24 04:25:41 · 5 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics
lim x>3(x-3)(x+2)/(x+3)(x-3)
lim=5/6
2006-09-24 04:27:48 · answer #1 · answered by raj 7 · 1⤊ 0⤋
Well, it can be factored:
x^2 - x- 6
------------
x^2 - 9
==
(x-3)(x+2)
--------------
(x-3)(x+3)
So, if x <> 3, this evaluates to (x+2)/(x+3)
The limit as x --> 3 would be (3+2)/(3+3) == 5/6
2006-09-24 11:52:42 · answer #2 · answered by felix_doc 2 · 0⤊ 0⤋
Differentiating the denominator and the numerator
lim (2x-1)/2x = 5/6
x>3
2006-09-24 11:43:38 · answer #3 · answered by rabi k 2 · 0⤊ 0⤋
It is in the form 0/0
take derivatives of numerator and denominator
2x-1 over 2x
for x=3
limit will be (2.3-1)/(2.3)=5/6
2006-09-24 11:31:37 · answer #4 · answered by iyiogrenci 6 · 0⤊ 0⤋
Data may be able to give you the answer he was the smartest goonie !
2006-09-24 11:30:06 · answer #5 · answered by Geronimo 3 · 0⤊ 0⤋