4x^2 + 40x + 64?

Question

factoring out completley/with all work

Answer 1

It would be like doing your homework for you. I can give you tips on how to set it up.
Since there are + signs only we know that it's gonna be
(x+ )(x+)
We also know that the x squared term becomes 4 and there are only two combinations which are 4 times 1 or 2 times 2.
(2x+)(2x+) or (4x+)(x+).
We know that the last term equals 64 which can be made in several ways ie 1 times 64 , 2 times 32 4 times 16, 8 times 8.
Experiment with the different combinations and you can answer it.

Answer 2

jazideol where the hell did you learn algebra...

4(x^2 + 10x + 16) ---- you were good here
4( x^2 + 2x + 8x + 16)------wth did you do here WRONG
4{ x( x+2) +8(x+2)}-----STILL WRONG
4{(x+2)(x+8)}-----------Right but what happened to the extra x and
that 8 from *8(x+2) and not to mention where did
(x+8) come from 8(x+2)
4(x+2)(x+8)
Now it supposed to be like :

4x^2 + 40x+64 we need to simplify we want
to find a number that will divided into all the factors to make it easier to work with. we will use 4
4(x^2+10x+16) now the hard part . Joe 17 already explained
it...and i don't like to repeat what was already said
4(x+2)(x+8)

hope this helped you

Answer 3

4x^2 + 40x + 64
4(x^2 + 10x + 16)
4( x^2 + 2x + 8x + 16)
4{ x( x+2) +8(x+2)}
4{(x+2)(x+8)}
4(x+2)(x+8)

Answer 4

4x^2 + 40x + 64
4(x^2 + 10x + 16)
4( x^2 + 2x + 8x + 16)
4{ x( x+2) +8(x+2)}
4{(x+2)(x+8)}
4(x+2)(x+8)

Answer 5

4x^2 + 40x + 64
4(x^2 + 10x + 16)
4( x^2 + 2x + 8x + 16)
4{ x( x+2) +8(x+2)}
4{(x+2)(x+8)}
4(x+2)(x+8)

Answer 6

(4x + 8) (x + 8)

Answer 7

Wow, you should really do your own homework.