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Convert the following equations to rectangular form and state the range of values for x and y.

x = 2sintcost, y = 3csc2t 0 < t < (Pi/2)

2006-09-24 03:49:20 · 3 answers · asked by Johnny 3 in Science & Mathematics Mathematics

3 answers

x = 2sin t cos t = sin 2t
y = 3cosec 2t = 3/sin 2t = 3/x
so y=3/x
it's a rectangular hyperbola in the form xy =c^2
where c=V3

for 0 to pi/2 it's basically filling the 1st quadrant only.

Hope this helps!

2006-09-24 04:00:31 · answer #1 · answered by yasiru89 6 · 0 0

x = 2sintcost, y = 3csc2t 0 < t < (Pi/2)
x = sin 2t, y = 3/ sin 2t
y =3/x
xy =3

2006-09-24 04:00:17 · answer #2 · answered by Amar Soni 7 · 0 0

Somewhat larger than a bread-box.

2006-09-24 04:20:35 · answer #3 · answered by Anonymous · 0 0

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