lim ...............(x^2 - 9)/(x^3 + 27)
x=>-3
2006-09-24 03:05:17 · 4 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics
The rule just states that if the limit becomes indeterminate (0/0 or infinity/infinity), then you should be able to find it by taking the quotient of the dervatives of the dividend and divisor. Using the power rule, we produce:
d numerator dx = 2x
d denominator dx = 3x^2
The solution logically follows with the quotient.
2006-09-24 03:14:47 · answer #1 · answered by Steven X 2 · 0⤊ 0⤋
when you allow x=3 you get the 0/0 indeterminate form
so using the L Hospital's rule
limx>-3 (2x-9/3x^2+27)=-6-9/27+27
=-3/54=-1/18
2006-09-24 10:10:16 · answer #2 · answered by raj 7 · 1⤊ 0⤋
-2/9 by L'Hopital or just factor and cancel out (x+3)
2006-09-24 10:23:27 · answer #3 · answered by rwbblb46 4 · 0⤊ 0⤋
diff num and denominator
=2x/3x2
=1/3x
putting value
2/9
2006-09-24 10:25:40 · answer #4 · answered by ishu pal s 1 · 0⤊ 0⤋