the point P(1,10) and Q(4,4). a) find equation of the PB of PQ b) this Pb intersects x-axis find cordinate?

Answer 1

equation of PQ=(y-y1)/(y2-y1)=(x-x1)/(x2-x1)
=(y-10)/-6=(x-1)/3
cross multiplying
3y-30=-6x+6
=>6x+3y-36=0
dividing throughout by 3
2x+y-12=0
what is the equation of the PB of PQ?
what is PB?

Answer 2

The slope is (4-10)/(4-1) = -6/3 = -2 so
y = -2x + b Substitute a point and solve for b
4 = -2*4 + b => b = 12 so the equation is
y = -2x +12

x intercept is when y = 0 so
0 = -2x + 12 => x = 6


Doug

Answer 3

Your forgot to type the point Bs coordinates

Ana