U-Tube Pressure Question!?

Question

A U-shaped tube, open to the air on both ends, contains mercury. Water is poured into the left arm until the water column is 16.2 deep.
How far upward from its initial position does the mercury in the right arm rise?

Any Help Would Be Appreciated Thx!

Answer 1

It would help if you were to indicate the volume & density of mercury.

Answer 2

Well, mercury has a specific gravity of about 13.55. Therefore, after adding water, you can take the level of mercury on the left (water) side as the reference point. For the weight of water and mercury to balance, the level of mercury on the right side will be:

h = 16.2/13.55 = 1.20 above the mercury on the left side

Since the level difference is twice the shift in height on each side, the column on the right arm moved up by 1.20 / 2 = 0.60.

Answer 3

The Hg on the left side is going to go as far down as the Hg on the right goes up. So whatever the change, x, is, the Hg on the right stands 2x above the Hg on the left. You can ignore the Hg below the new level on the left, above which stands only the water. So you need (rho*g*h)_left = (rho*g*h)_right, and g is constant. So rho_water*h = rho_Hg*2x. Rho is density; you can look up the desnities of water and Hg. h is the given 16.2, but you'll need units. So x is your only unknown.

Answer 4

density of mercury versus water is needed, also the measurement of the U-tube, 16.2 what? meters or centimeters,...

the diameter of the U-tube, or circumference or radius needed, then the height ot 16.2 will be involve in geeting the volume of water that was added.

the density of water at standard room temperature and pressure is 1 gram per cubic centimeter.

get the volume of water in cubic centimeters, if the given measurements are not metric, convert your values to metric, you must know the convertion factor, covertion table needed.

Answer 5

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