if r(x)= 6x+5 and s(r(x))= 2x-1, then s(x)= ?
2006-09-23 19:44:43 · 8 answers · asked by ibid 3 in Science & Mathematics ➔ Mathematics
s(x) = 1/3 x - 8/3
2006-09-23 19:51:01 · answer #1 · answered by Demiurge42 7 · 0⤊ 0⤋
S(6x + 5) = 2x - 1
u/3 -8/3 ?
S(u) = u/3 - 8/3
S(6x + 5) = (6x + 5)/3 - 8/3 = 2x + 5/3 - 8/3 = 2x - 3/3 = 2x -1
Please check for errors
2006-09-24 02:53:13 · answer #2 · answered by Anonymous · 0⤊ 1⤋
s(6x+5)=2x-1
=1/3. [6x-3+8-8]
s(x)=1/3 . (x-8)
2006-09-24 03:39:14 · answer #3 · answered by iyiogrenci 6 · 0⤊ 1⤋
r(x) = 6x+5
s(r(x) = 2x-1
Let us see if r(x) can be inverted
r(x) = 6x+ 5
x= 6r^-1(x) + 5
r^-1(x) = (x-5)/6
s(r(x)) = 2x-1
so s(x) = 2(x-5)/6-1 = x/3- 8/3
2006-09-24 03:18:35 · answer #4 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
s(x)=2(6x+5)-1
s(x)=12x+9
2006-09-28 02:30:16 · answer #5 · answered by oana o 2 · 0⤊ 0⤋
r(x)=6x+5
s(r(x))= 2x-1
s(6x+5)=2x-1
s(x)=x/3-8/3
2006-09-24 04:51:36 · answer #6 · answered by Lin 2 · 0⤊ 0⤋
12x+9
2006-09-24 02:52:49 · answer #7 · answered by Anonymous · 0⤊ 1⤋
Your given is wrong
2006-09-24 02:49:40 · answer #8 · answered by Mad Dog 2 · 0⤊ 2⤋