very simple
1. Draw a line segment AC.
2. bisect it at O
3. draw any line L passing AC thru O.
4. cut OB and OD from line l such that OB = OD.
5. Join ABCD, ABCD is a parallelogram
coz AO=CO & OB=OD, ie, AC & BD bisect each other at O, which is a property of a parallelogram
2006-09-25 19:33:31
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answer #1
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answered by Yogesh G 3
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Draw two lines m and n which cross at point P. On line m find any two points A and B, one on either side of P, such that distance AP = distance BP. On line n find any two points C and D, one on either side of P, such that CP = DP. Notice that the distances used on the two lines do not have to be the same, that is, AP=BP does not have to be the same as CP=DP. Then ACBD is a parallelogram. This is true because the diagonals of a parallelogram always bisect one another.
2006-09-23 18:17:55
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answer #2
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answered by wild_turkey_willie 5
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Draw two parallel lines the exact same length, and then connect the ends of the lines with two more parallel lines. You should end up with something that looks like a leaning rectangle.
2006-09-23 17:58:51
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answer #3
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answered by cushdogjr 3
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Build a square or rectangle and lean on it, or make 2 parallel lines cross 2 other parallel lines on the same plane.
2006-09-23 18:06:41
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answer #4
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answered by ERIC G 3
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draw 2 parallel lines with the same length then connect its ends with another pair of parallel lines. Just be sure that none of the interior angles is equal to 90 degrees..
2006-09-23 18:25:47
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answer #5
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answered by ricorig 2
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Requirements-paper, scale, pencil.
Construct 2 parallel lines vertically and joined it horizontally if not samajdhar take help from a book or call me at 2548837
2006-09-23 18:13:47
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answer #6
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answered by bikash p 1
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http://mathforum.org/dr.math/faq/formulas/faq.quad.html#parallelogram
basically its like a rectangle only pushed in opposite directions.
2006-09-23 18:34:10
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answer #7
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answered by Sherman81 6
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