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3 answers

To find the probability of the second of two dependent events is a pretty easy task.

A good example is pulling a card out of a standard deck of 52 cards. Lets say you want to pull a red jack, then a black ace.

First, the probability of the red jack. there are 2 in a deck so the probability is 2/52 or,reduced, 1/26.
Then find for the black aces. There are 2 in a deck, but now since there are only 51 cards in the deck now that you already took one out, the probability is 2/51.

If you wanted to find the combined probability, you would multiply the two numbers.
1/26x2/51= 2/1326 or, reduced, 1/663

2006-09-23 16:38:22 · answer #1 · answered by american_girl_24_7 1 · 0 0

Hi. Assuming the first event occurs favorably and the second event's probablility is known then it is simply the second events probability. The total would be #1 times #2 as a percent. (30% times 60% equals 18%.)

2006-09-23 16:26:12 · answer #2 · answered by Cirric 7 · 0 0

Use Bayes' theorem.

(let A intersection B be denoted by AB).

P (AB) = P (A/B) * P(B).= P(B/A)*P(A)

So, P(B) = P(AB)/P(A/B).

2006-09-23 17:47:37 · answer #3 · answered by jinxy 2 · 0 0

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