which reqires more work to stop? a heavier truck or a lighter truck with the same momentum?

Answer 1

equal, if they hit each other, they will both stop

Answer 2

If you mean by "work" the energy needed to stop the trucks, there is a difference. momentum is m*v, and energy is .5*m*v^2. Therefore energy can be written E = .5*M*v, where M is the momentum. Since M = mv, v=M/m so E = .5 M^2/m. For M the same in both cases, the lighter truck has more energy, and therefore will require more work to stop.

Answer 3

Momentum=mass*velocity. easy tract have lesser mass than heavy truck.yet while they have same momentum thier velocity ought to be diverse. occasion, easy truck have 50kg mass and velocity 4m/s. So the momentum could be 2 hundred.and if heavy truck have 100kgmass and 2m/s. So the momentum could be same 2 hundred. So the two autos have diverse velocity and diverse mass.rigidity=mass*acceleration.yet acceleration is substitute in velocity. So,rigidity is the cost of substitute of momentum which relies upon on time element. so as I mentioned above, they might have same momentum yet thier time difference occurs,so time element is needed to respond to your question completly. purely you will get the sufficient explaination from pearlsaw. She is real and that i dont understand why she have been given thumbs down.

Answer 4

Work is force times distance. It is also the change in kinetic energy. Even though the two trucks have the same momentum, they don't have the same kinetic energy - figure out which has more kinetic energy (make up some numbers if you have to) and that one will require more work to stop.

Answer 5

The lighter one. KE goes up as the square of the velocity, but momentum is directly proportional to v.

Answer 6

they both require the same work to stop

Answer 7

yeah, i think it's equal