Thanks for any help!
2006-09-23 12:04:37 · 7 answers · asked by Gypsophila 3 in Science & Mathematics ➔ Mathematics
implicit differention on xy just means finding the derivative of an equation or expression when y (or the variable of interest) is not isolated. the steps are basically the same. xy differentiated would be x(dy/dx)+y. we used the product rule.
2006-09-23 12:19:37 · answer #1 · answered by need help! 3 · 0⤊ 0⤋
Differentiate Xy
2016-11-09 22:47:02 · answer #2 · answered by ? 4 · 0⤊ 0⤋
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How would you differentiate xy using implicit differentiation?
Thanks for any help!
2015-08-19 02:12:16 · answer #3 · answered by Viv 1 · 0⤊ 0⤋
Differentiate xy using implicit differentiation
Let xy =k where k is constant
(x)(differentiate y w.r.t x)+(y)(differentiate x w.r.t x) =0
x)(dy/dx)+(y)(1) =0
dy/dx = -(y)
2006-09-23 12:45:42 · answer #4 · answered by Amar Soni 7 · 0⤊ 1⤋
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When you take the derivative of y, you put a (dy/dx) in front of it. And make sure you remember to use the product rule: y' = f(x)g'(x) + g(x)f'(x) xy x(1)(dy/dx) + y(1) x(dy/dx) + y Hope this helps!
2016-04-10 04:43:42 · answer #5 · answered by Anonymous · 0⤊ 0⤋
you didnt say what xy equaled, so we'll assume 0
d/dx { xy} = d/dx{0)
x * dy/dx + y*1 = 0
dy/dx = -y/x
2006-09-23 12:16:42 · answer #6 · answered by KDRdoc 2 · 2⤊ 0⤋
d/dx(xy)+d/dy(xy)=y+x
2006-09-23 13:12:32 · answer #7 · answered by Mattie123 1 · 1⤊ 1⤋
y(dx/dx)+x(dy/dx)= =y+x(dy/dx)
2016-03-18 08:14:07 · answer #8 · answered by Anonymous · 0⤊ 0⤋