2006-09-23 11:46:54 · 6 answers · asked by cstoa10 5 in Science & Mathematics ➔ Mathematics
prime factor each number
start with 2 and find the biggest number of 2's in any of the 3 numbers. write this down
repeat with 3's writing down biggest number of 3's in any of the numbers
repeat for each unique factor in any of the numbers until youve done so for every factor in all of thre numbers
now the group of numbers youve written down is multiplied together and this number is the LCM
12=2*2*3 16=2*2*2*2 10=2*5
so biggest number of 2's is 4 so i write down 2*2*2*2
1 is biggest number of 3's write down a 3 we
have2*2*2*2*3
only 1 5 so we write down this too and we have
2*2*2*2*3*5
LCM=2*2*2*2*3*5=16*3*5=16*15=240 so yes you were right!!
2006-09-23 11:59:02 · answer #1 · answered by ivblackward 5 · 2⤊ 0⤋
12 = 3x4 = 3 x 2^2
16 = 4x4 = 2^2 x 2^2 = 2^4
10 = 2 x 5
Now lets review how you find the least common multiple: you have to pick all the factors to their bigger power.
So: 3 and 5 are part of the LCM
Among 2, 2^2 and 2^4, you have to choose the last one
So the LCM is 3 x 5 x 2^4 = 15 x 16. Just pick a calculator or do this by hand
Ana
2006-09-23 19:03:39 · answer #2 · answered by MathTutor 6 · 1⤊ 0⤋
yes it is. the fastest way to determine the LCM is to find the prime denometers of the three numbers and combine them:
12: 2*2*3
16: 2*2*2*2
10: 2 * 5
2*2*2*2*3*5 = 240
for each repeated number, you only use it the most number of times it appears in one section. The nuymber 2 appears four times for 16 so that's how many times you will use it. Hope this helps.
2006-09-23 19:19:26 · answer #3 · answered by Nikitty 2 · 1⤊ 0⤋
10 : 2 * 5
12 : 2 * 2 * 3
16 : 2 * 2 * 2 * 2
2 * 5 * 2 * 3 * 2 * 2 = 240
2006-09-23 21:04:05 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
looks good to me.
2006-09-23 18:50:45 · answer #5 · answered by Duckie 3 · 1⤊ 0⤋
yes, it is.
2006-09-23 21:01:27 · answer #6 · answered by chococat 4 · 0⤊ 0⤋