the square of a number is 56 more than the number its self. what is the number?
2006-09-23 10:56:24 · 9 answers · asked by ballet_tigger 3 in Science & Mathematics ➔ Mathematics
let the no. be = x
x^2= x+56
x^2-x-56=0
x^2- 8x +7x - 56=0
therefore x= -7 0r x= 8
2006-09-23 11:04:56 · answer #1 · answered by Angad 4 · 3⤊ 0⤋
8
2006-09-23 18:18:04 · answer #2 · answered by jordanthegrouch 3 · 0⤊ 0⤋
Simple equation x^2 - x - 56 = 0
Solution x = 8 or -7
2006-09-23 22:12:25 · answer #3 · answered by small 7 · 0⤊ 0⤋
x^2 = 56 + x
x^2 - x -56=0
(x-8)(x+7) =0
Therefore
x =8 or x= -7
2006-09-23 18:03:58 · answer #4 · answered by Amar Soni 7 · 1⤊ 0⤋
x2 = 56+x
x2-x=56
x2-x-56=0
(x-8) (x+7)=0
x=8, x= -7
2006-09-23 18:00:47 · answer #5 · answered by knifelvr 4 · 1⤊ 0⤋
That is not a riddle. It is 8.
2006-09-23 17:59:30 · answer #6 · answered by Barkley Hound 7 · 0⤊ 0⤋
8 squared = 64
64-56 = 8
Sounds like homework to me.......hmmmmm
2006-09-23 18:04:24 · answer #7 · answered by MARY L 5 · 0⤊ 0⤋
3,136
You just square the number and thats the number.
2006-09-23 18:00:31 · answer #8 · answered by Anonymous · 0⤊ 1⤋
silly lady fish can't do math, how am i supposed to answer this? maybe 28?
2006-09-23 18:00:59 · answer #9 · answered by Big L 2 · 0⤊ 1⤋