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In hABC, b=3, c=4, and A=45degrees. Expreesed in simplest radical form, what is the area of hABC?
What i want to find out is what is the meaning of "h" in "hABC"?

2006-09-23 10:55:40 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

area=1/2bcsinA
=1/2(3)(4)*rt2/2
=3rt2 square units

2006-09-23 11:01:03 · answer #1 · answered by raj 7 · 0 0

Rfamilymember's got 'almost' the right answer for the area (as he usually does ☺). It should be 6*√2/2.

But as to what the h stands for....... You got me. I would have expected the little 'triangle drawing' (it's technical name is 'delta'). Maybe it's a misprint?


Doug

2006-09-23 18:18:43 · answer #2 · answered by doug_donaghue 7 · 0 0

sorry never done hyperbolic triangles, but maybe these sites will help

www.maths.gla.ac.uk/~wws/cabripages/hyperbolic/hsegments.html

www.maths.gla.ac.uk/~wws/cabripages/hyperbolic/harea.html

www.geom.uiuc.edu/java/triangle-area/

2006-09-23 21:35:13 · answer #3 · answered by Sherman81 6 · 0 0

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