Integration by parts - Step by step
2006-09-23 09:58:44 · 5 answers · asked by thegame1083 1 in Science & Mathematics ➔ Mathematics
∫(e^-x) x^2 dx = -((2 + x(2 + x)) / e^x) +c
It was your last question, hope see you soon.
Good Luck Robert .
2006-09-23 10:22:16 · answer #1 · answered by sweetie 5 · 1⤊ 0⤋
Check out http://integrals.wolfram.com/index.jsp
Great site âº
Doug
2006-09-23 17:45:12 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
easy problem
pl see a good website...and the text book....
a good one is http://archives.math.utk.edu/visual.calculus/4/int_by_parts.1/index.html
2006-09-23 17:05:12 · answer #3 · answered by m s 3 · 0⤊ 0⤋
im sorry.
i really wish i could help.
and i hate to take advantage of these points.
but sadly i must.
thnx.
2006-09-23 17:09:11 · answer #4 · answered by tishathedragon 1 · 0⤊ 0⤋
let e^-x=dv and x^2=u integrating by partsuv-int vdu
= x^2(-e^-x)-int(-e^-x)(2x)again integrating by parts
with e^-x as dv and x as u
=-x^2e^(-x)+2[x(-e^(-x)-int(-e^(-x)dx
=-x^2e^(-x)-2xe^(-x)-2(-e^(-x)+C
=-x^2e^(-x)-2xe(-x)+2e^(-x)+C
2006-09-23 17:16:34 · answer #5 · answered by raj 7 · 0⤊ 0⤋