Q. Find four consecutive integers whose sum in twice the cube of 5
What it the set up and answer?
2006-09-23 09:54:45 · 3 answers · asked by eatitnow21 1 in Education & Reference ➔ Homework Help
5^3 * 2 = 250
let x represent the consecutive numbers
x +( x+1 +(x+2 +( x+3 = 250
4x +6 = 250
4x = 250 -6
4x= 244
x= 61
so the numbers are 61 , 62,63, 64
because they are consecutive numbers that is why you have + 1 ,2,3 because they keep increasing by 1
2006-09-23 10:01:39 · answer #1 · answered by Anonymous · 1⤊ 0⤋
The consecutive integers are 30,31,32,33. First take 5x5=25x5=125x2=250 (the double of 5 cubed).Then go through the numberline.
2006-09-23 09:59:32 · answer #2 · answered by poker man 2 · 0⤊ 3⤋
(x+(x+1)+(x+2)+(x+3))= 2(5^3)
4x+6 = 2(5^3)
Try working it out.
2006-09-23 10:00:42 · answer #3 · answered by Gordo J 2 · 0⤊ 0⤋