what would be the step by step way to solve the equation,
(4y - 3) - (4 - y)= 3( y + 3) to find the solution?
2006-09-23 09:14:17 · 8 answers · asked by eatitnow21 1 in Education & Reference ➔ Homework Help
Problem: (4y-3)-(4-y)=3(y+3)
1. (4y-3)-(4-y)=3y+9
2. 4y-3-4+y=3y+9
3. 5y-7=3y+9
4. 2y-7=9
5. 2y=16 (then divide by 2)
y=8
Hope this helps...:)
2006-09-23 09:19:58 · answer #1 · answered by majorlanceandthewizard 1 · 0⤊ 0⤋
distribute the negative to the (4-y) and the 3 to the (y+3). u then have 4y - 3 - 4+y= 3y +9
when u have that, just add and subtract the like terms. u'll get
5y-7=3y+9
then do the same here, but by subtracting and adding terms from side to side. u'll get
2y=16
divide and u get y=8
2006-09-23 16:18:17 · answer #2 · answered by naomi 2 · 0⤊ 0⤋
4y-3-4+y=3y+9
5y-7=3y+9
+7 +7
5y = 3y +16
-3y -3y
2y = 16
2y/2 = 16/2
y=8
2006-09-23 16:19:55 · answer #3 · answered by Yup! I'm a girl! 2 · 0⤊ 0⤋
First do te math on the right side.
3(y+3) = 3y+9
Then do the math on the left side (subtraction)
Then move the integer to the right by adding it to both sides.
Then move the "y" to the left by subtracting it from both sides.
Then solve.
2006-09-23 16:18:11 · answer #4 · answered by musiclady007 4 · 0⤊ 0⤋
removing the brckets
4y-3-4+y=3y+9
transposing
5y-3y=9+7
2y=16
y=8
2006-09-23 16:18:21 · answer #5 · answered by raj 7 · 0⤊ 0⤋
4y-3-4+y=3y+9
5y-7=3y+9
2y-7=9
2y=16
y=8
2006-09-23 16:17:27 · answer #6 · answered by cabjr1961 4 · 0⤊ 0⤋
(4y-3)-(4-y)=3(y+3)
4y-3-4+y=3y+9
4y+y-3y=9+3+4
2y=16
y=8
2006-09-23 16:21:11 · answer #7 · answered by Anonymous · 0⤊ 0⤋
is this your homework? Wha grade are you in?
2006-09-23 16:16:36 · answer #8 · answered by Argent 4 · 0⤊ 0⤋