i placed isosceles triangles too. indexed right here are the solutions for section 2, 3 and four: 29 20 the two a million/2 of the fringe of the vast triangle or upload a million/2 the lengths of the two factors 30 3 arcs had to construct a perpendicular from a element no longer on the line 31 y = -2x+14 32 2 X for intersections of locus, perpendicular bisector a million.5? from each and each endpoint and a circle with radius 2? from A 33 real, disjunction is real if any section is real 34 20 set 2 congruent angles equivalent to a minimum of one yet another and clean up for x 35 SE = 18 considering that tangent from the comparable element are congruent, x+3x=24, x=6 and 3x=18 36 15 + 5 radical 5 , use 3 distance formula(pythagorean Theorem) 37 A(0,-a million) B(-5,2) C(-6,-a million) D(-a million,-4) 38 Vertical angles are congruent, midpoint cuts a phase into 2 congruent segments, SAS , CP in congruent triangles are congruent, If substitute indoors angles are congruent, then the lines are parallel.
2016-10-17 12:38:39
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answer #2
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answered by ? 4
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