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How much force act on it when it reaches its peak?

2006-09-23 07:52:03 · 5 answers · asked by lilv 1 in Science & Mathematics Physics

5 answers

depends on force applied

2006-09-23 07:55:33 · answer #1 · answered by confused 2 · 0 3

Hi. After the coin accelerates during the toss, air resistance and 1 g of gravity. At its peak just 1 g.

2006-09-23 07:54:31 · answer #2 · answered by Cirric 7 · 1 1

Gravity is constant at all times. Air resistance is more difficult to compute, and is often ignored for purposes of teaching.

Once the coin loses contact with the "flipper", there are no other forces being applied.

2006-09-23 08:16:34 · answer #3 · answered by Zhimbo 4 · 0 0

There would only be two forces acting on the coin. First its weight which would be equal to its mass times the accleration of gravity. Second the force of air resistance which is proportional to its mass, cross sectional area, and velocity.

2006-09-23 07:54:57 · answer #4 · answered by msi_cord 7 · 1 0

Mathew I is correct EXCEPT that mass has no effect on the force of air friction

2006-09-23 08:10:47 · answer #5 · answered by curious george 5 · 0 0

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