find f(1/2) if f(x)=x to the power of 3 + x to the power of 2 -2x+3?

Question

i need to review my calculus. can anyone show me how to get the answer, not just the answer but the steps please.
thx

Answer 1

if x = 1/2 then:
x to the power of 3, also noted x^3 = 1/8
x to the power of 2, noted x^2 = 1/4

f(1/2) = 1/8+ 1/4 -1+3 = 2 3/8

Answer 2

f(1/2) = (1/2)^3 + (1/2)^2 - 2*(1/2) + 3
= 1/2^3 + 1/2^2 -2/2 + 3
= 1/8 + 1/4 - 1 + 3

Answer 3

It's not really calculus, just plug 1/2 into the equation for x

x^(3+x)^2-2x+3

That doesn't look right... but i'll answer it from here

1/2^(3+1/2)^-2(1/2)+5

1/2^(3+1/2)^4

1/2^(7/2)^4

just simplify and that's it
so 1/2

Answer 4

f(1/2) = (1/2)^3 + (1/2)^2 - 2(1/2) + 3
f(1/2) = (1/8) + (1/4) - 1 + 3
f(1/2) = (1/8) + (1/4) + 2
f(1/2) = (1/8) + (2/8) + (16/8)
f(1/2) = (1 + 2 + 16)/8
f(1/2) = (19/8) or 2 3/8

Answer 5

f(x)=x^(3+x)^(2-2x+3)
f(1/2)= (1/2)^(7/2)^(4)
=(1/2)^14=1/(2^14)

Answer 6

and what grade are u in? i have no clue, but thanx 4 the 2 points!