How do I balance this equation?

Question

C3H5O9N3 -------> CO2 + N2 + O2 + H2O

Answer 1

4C3H5O9N3 -------> 12CO2 + 6N2 + O2 + 10H2O

Answer 2

Start by balancing an element the occurs only once on each side of the equation (avoid Oxygen in this case), so I pick N to balance first, and hope everything else falls in place.

x*C3H509N3 = would give y*N2

for x *3 N atoms in the molecule to form y*N2 I would try using x=2 and that would fix y = 3, does that balance out everything else?

Lets see:

2 C3H5O9N3 = 6*CO2 + 3*N2 + kO2 + 5* H20

how many O2 would we need to finish this properly?
On the left we have 18 Oxygen atoms, on the right 17 + 2K

Then K would have to be 1/2, to deal with an equation with whole numbers is more desirable, so multiply each side by 2
4 C3H5O9N3 = 12*CO2 + 6*N2 + O2 + 10*H20

Please check for errors

Answer 3

You look for the number of atoms present on the reactant side and the product side. Then you place a certain number at the beginning of the atom, molecule, or compount ion such a way that the number of the atoms on product side is equal to the number of the atoms on the reactant side. And you do this in a way that it is consistent with each element present. So ig you have 3 C on reactant sides then you should have 3 on the other side.

Answer 4

4C3H5O9N3---->12CO2 + 6N2 + O2 + 10H2O..indeed

Answer 5

4C3H5O9N3 -> 12CO2 + 6N2 + 10H2O +O2

Answer 6

4C3H5O9N3----->12CO2 + 6n2 + O2 + 10H2O

Answer 7

reply alreay given is ok