2006-09-23 04:41:23 · 6 answers · asked by Mimi 2 in Science & Mathematics ➔ Mathematics
This is not a point
basically this is
x^2+y^2-y+z^2=0
or x^2+(y-1/2)^2+z^2 -1/4=0 becuase y^2-y = y^2-2*2y/2 +1/4-1/4
= (Y-1/2)^2-1/4
or x^2 +(Y-1/2)^2+Z^2= (1/2)^2
So this is a sphere with centre (0,1/2,0) and radius 1/2
2006-09-23 21:20:21 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
x^2 + y^2 + z^2 -y = 0 is a point (0,0,0).
But the -y term is a bit confusing.. As thermo said, it can mean a set of points.
If you have x=0, z=0 then you have y^2 = y which can mean (0,0,0) or (0,1,0).
2006-09-23 11:47:14 · answer #2 · answered by astrokid 4 · 0⤊ 0⤋
Yes. It is the point (0 , 0 , 0)
The minus y makes me believe it could be a set of points,
but I can't find them.
Th
2006-09-23 11:46:28 · answer #3 · answered by Thermo 6 · 0⤊ 0⤋
It's a spheroid with an origin at (0,.5,0). It's long axis extends along the Y-axis from (0,0,0) to (0,1,0). At it's widest point (when Y is 0.5), it's radius from the Y-axis is 0.25.
2006-09-23 12:09:23 · answer #4 · answered by Bob G 6 · 0⤊ 0⤋
Definitely not due to the -y term.
2006-09-23 11:45:11 · answer #5 · answered by bruinfan 7 · 0⤊ 0⤋
no
2006-09-23 11:46:02 · answer #6 · answered by rwbblb46 4 · 0⤊ 0⤋