a train travelling at 22mph, a car travelling at 89mph, how long 4 the car 2 catch up if the train left 4h b4?

Answer 1

The speed difference is (89-22)= 67; because the train had a four hour head start, it is already (22*4)=88 miles ahead of the car. It would take the car (88/67) = 78.8 minutes to catch the train.

Answer 2

distance(s)= speed(v) * Time(t)
so s=vt and the distance for both is the same
for the train (s=v1+t1) plug in the numbers and it becomes s=22(t+4)
for the car it becomes s=89t
so 22(t+4)=89t
22t+88=89t
88=67t
t=88/67 or about 1.31 hours/ 78.6 minutes

Answer 3

The answer can be given only if the initial distance is known.
The time can be calculated with
initial distance = time x (speed of car - speed of train) or
time = initial distance / (speed of car - speed of train)
When the question is 'how long'? the initial moment does not play a role nor the moment of catching.

Th

Answer 4

88/67 hours