It's not one equation; it's an example of simultaneous equations:
x + 2y = 57
x + y = 42
I'm glad to hear you've got the answer.
2006-09-23 03:38:41
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answer #1
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answered by bearhill13 2
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the sum of two numbers is 42:
a + b = 42
first number + 2x second number is 57:
a + 2b = 57
(that's how you write the equations);
right now you can see that b = 15, because the difference between a+b and a+2b is 15;
a = 27 because since b = 15, 2b = 30; so 57 - 30 = 27.
OR you can solve the system of equations; here are the steps:
find the value of one variable in terms of the other one:
a + b = 42
a = 42 -b
now substitute that value for the other var, and solve:
(42 - b) + 2b = 57
42 + b = 57
b = 57 - 42
b = 15
now substitute the value of b back into the first equation to find the value of a:
a + b = 42
a + 15 = 42
a = 42 - 15
a = 27
and you're done! good luck!
2006-09-23 12:19:51
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answer #2
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answered by ronw 4
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It can be solved by one equation.
Let x = 1st number
42-x = 2nd number
x + 2(42 - x) = 57
x + 84 - 2x = 57
-x = -27
x = 27
42 - x = 15
To check:
27 + 15 = 42 and 27 + 30 = 57
2006-09-23 10:44:51
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answer #3
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answered by edconda 2
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x + y = 42; x + 2y = 57
2006-09-23 10:41:56
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answer #4
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answered by Kirlia 2
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Let x be one number. then 42-x is the other number.
x + 2(42-x) = 57
2006-09-23 10:41:54
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answer #5
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answered by whatthe 3
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x + y = 42
x + 2y = 57
x = -2y + 57
(-2y + 57) + y = 42
-2y + 57 + y = 42
-y = -15
y = 15
x = -2(15) + 57
x = -30 + 57
x = 27
ANS : 27 and 15
2006-09-23 14:29:36
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answer #6
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answered by Sherman81 6
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a+b=42
a+2b=57
to solve subtract one equation from the other
2b-b=57-42
b=15
substitue the 15 for b to get a
a+15=42
a=27
(a,b)=(27,15)
2006-09-23 10:49:58
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answer #7
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answered by Anonymous
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its simultaneous equation
x+y=42
x+2y=57
(x+2y)-(x+y)=57-42
y=15
x=42-15
x=27
2006-09-23 11:34:06
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answer #8
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answered by bookwormanu 2
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Your teacher can help
2006-09-23 10:36:22
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answer #9
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answered by Anonymous
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